F(x)=x^2/3

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Solution for F(x)=x^2/3 equation:



(F)=F^2/3
We move all terms to the left:
(F)-(F^2/3)=0
We get rid of parentheses
-F^2/3+F=0
We multiply all the terms by the denominator
-F^2+F*3=0
We add all the numbers together, and all the variables
-1F^2+F*3=0
Wy multiply elements
-1F^2+3F=0
a = -1; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·(-1)·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*-1}=\frac{-6}{-2} =+3 $
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*-1}=\frac{0}{-2} =0 $

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